More on (moron?) the 9 single-A pitcher strategy
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More on (moron?) the 9 single-A pitcher strategy
On Mike and Mike this morning, they were talking about Braden Looper's ERA of infinity. Got me thinking about the 9 single-A pitcher strategy in the NFBC. Suppose a team had 8 inactive pitchers and Braden Looper. Let's also say that Braden Looper blew out his elbow yesterday, and was lost for the season. A further assumption: the team made no other pitching changes for the rest of the season. The team's ERA would be infinity, but...
would that put that team in last place overall in ERA, or
would they be tied with the other teams that had zero innings pitched on the season?
Real stupid question, but then again, maybe not. Keep in mind that both situations would result in a team having zero innings pitched.
would that put that team in last place overall in ERA, or
would they be tied with the other teams that had zero innings pitched on the season?
Real stupid question, but then again, maybe not. Keep in mind that both situations would result in a team having zero innings pitched.
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More on (moron?) the 9 single-A pitcher strategy
How's this for a guess...The teams with o innings would be ranked by runs allowed.
More on (moron?) the 9 single-A pitcher strategy
Well.. being a programmer I think I can answer this question for you.
ERA is (Earned Runs*9)/Innings Pitched..
so a pitcher who gives up 3 runs in a 9 inning game..
(3*9)/9 = 3.00 era
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year)
ERA is (Earned Runs*9)/Innings Pitched..
so a pitcher who gives up 3 runs in a 9 inning game..
(3*9)/9 = 3.00 era
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year)
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More on (moron?) the 9 single-A pitcher strategy
Originally posted by JAR:
Well.. being a programmer I think I can answer this question for you.
ERA is (Earned Runs*9)/Innings Pitched..
so a pitcher who gives up 3 runs in a 9 inning game..
(3*9)/9 = 3.00 era
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year) Duh....
(3*9)/0 does not equal 0
Well.. being a programmer I think I can answer this question for you.
ERA is (Earned Runs*9)/Innings Pitched..
so a pitcher who gives up 3 runs in a 9 inning game..
(3*9)/9 = 3.00 era
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year) Duh....
(3*9)/0 does not equal 0
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More on (moron?) the 9 single-A pitcher strategy
Originally posted by JAR:
Well.. being a programmer I think I can answer this question for you.Great! I've come to the right place.
Originally posted by JAR:
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year) Thanks for the chuckle.
Well.. being a programmer I think I can answer this question for you.Great! I've come to the right place.
Originally posted by JAR:
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year) Thanks for the chuckle.

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More on (moron?) the 9 single-A pitcher strategy
Originally posted by JAR:
Well.. being a programmer I think I can answer this question for you.
ERA is (Earned Runs*9)/Innings Pitched..
so a pitcher who gives up 3 runs in a 9 inning game..
(3*9)/9 = 3.00 era
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year) JAR, I surely hope you don't get paid alot for your analysis. I am guessing you are STRICTLY a programmer (and avoid any type of analytical work) after that post
Well.. being a programmer I think I can answer this question for you.
ERA is (Earned Runs*9)/Innings Pitched..
so a pitcher who gives up 3 runs in a 9 inning game..
(3*9)/9 = 3.00 era
Since Looper gave up 3 runs, and had 0 IP.. that is..
(3*0)/9 = 0.00 era
So his 3 ER would be the same as 0 ER (assuming his team does not accumulate any IP the entire year) JAR, I surely hope you don't get paid alot for your analysis. I am guessing you are STRICTLY a programmer (and avoid any type of analytical work) after that post

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More on (moron?) the 9 single-A pitcher strategy
Quite seriously, JAR's response might be one of the funniest posts of the season. As Bill Simmons might say, he scored very well on the Unintentional Comedy Scale.
More on (moron?) the 9 single-A pitcher strategy
Originally posted by JerseyPaul:
(3*9)/0 does not equal 0 I never said it did.. I said 3*0/9 = 0
But you're right.. I was being stupid.. the correct way to calculate it is (3*9)/0.. which of course is impossible to compute because you cannot divide by 0.
But in my defense.. the answer would still be 0, because ERA is a number, and you can't represent infinity in a numerical field within a database.
So the programmer for STATS would write a line of code like... if(IP != 0)){ ERA = runs*9/IP; } else { ERA = 0; }
[ April 06, 2005, 03:30 PM: Message edited by: JAR ]
(3*9)/0 does not equal 0 I never said it did.. I said 3*0/9 = 0
But you're right.. I was being stupid.. the correct way to calculate it is (3*9)/0.. which of course is impossible to compute because you cannot divide by 0.
But in my defense.. the answer would still be 0, because ERA is a number, and you can't represent infinity in a numerical field within a database.
So the programmer for STATS would write a line of code like... if(IP != 0)){ ERA = runs*9/IP; } else { ERA = 0; }
[ April 06, 2005, 03:30 PM: Message edited by: JAR ]
More on (moron?) the 9 single-A pitcher strategy
Actually if the programmer were intelligent they would write that same line of code but with the result of the then statement being the largest possible era since basic proofs show that any number divided by 0 will approach infinity you would automatically set ERA = to the largest value that numeric field could possibly hold thus representing the closest approximation allowable within the confines of the table structure used to hold that value...
-DOH-
More on (moron?) the 9 single-A pitcher strategy
Originally posted by mrphikapp:
Actually if the programmer were intelligent they would write that same line of code but with the result of the then statement being the largest possible era since basic proofs show that any number divided by 0 will approach infinity you would automatically set ERA = to the largest value that numeric field could possibly hold thus representing the closest approximation allowable within the confines of the table structure used to hold that value... Indeed, that's my feeling, too.
Dyv
Actually if the programmer were intelligent they would write that same line of code but with the result of the then statement being the largest possible era since basic proofs show that any number divided by 0 will approach infinity you would automatically set ERA = to the largest value that numeric field could possibly hold thus representing the closest approximation allowable within the confines of the table structure used to hold that value... Indeed, that's my feeling, too.
Dyv
Just Some Guy
More on (moron?) the 9 single-A pitcher strategy
Originally posted by Dyv:
quote:Originally posted by mrphikapp:
Actually if the programmer were intelligent they would write that same line of code but with the result of the then statement being the largest possible era since basic proofs show that any number divided by 0 will approach infinity you would automatically set ERA = to the largest value that numeric field could possibly hold thus representing the closest approximation allowable within the confines of the table structure used to hold that value... Indeed, that's my feeling, too.
Dyv [/QUOTE]Like 99.99
quote:Originally posted by mrphikapp:
Actually if the programmer were intelligent they would write that same line of code but with the result of the then statement being the largest possible era since basic proofs show that any number divided by 0 will approach infinity you would automatically set ERA = to the largest value that numeric field could possibly hold thus representing the closest approximation allowable within the confines of the table structure used to hold that value... Indeed, that's my feeling, too.
Dyv [/QUOTE]Like 99.99
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More on (moron?) the 9 single-A pitcher strategy
Originally posted by JAR:
But you're right.. I was being stupid.. But in my defense.. the answer would still be 0, because ERA is a number, and you can't represent infinity in a numerical field within a database.
So the programmer for STATS would write a line of code like... if(IP != 0)){ ERA = runs*9/IP; } else { ERA = 0; } If a train is leaving Chicago at exactly 3pm, carrying 500 passengers, and is heading towards Las Vegas, and at the EXACT SAME MOMENT, another train is leaving New York, with 400 passengers, heading towards Iola...
...would a programmer say that the ERA is still zero?
But you're right.. I was being stupid.. But in my defense.. the answer would still be 0, because ERA is a number, and you can't represent infinity in a numerical field within a database.
So the programmer for STATS would write a line of code like... if(IP != 0)){ ERA = runs*9/IP; } else { ERA = 0; } If a train is leaving Chicago at exactly 3pm, carrying 500 passengers, and is heading towards Las Vegas, and at the EXACT SAME MOMENT, another train is leaving New York, with 400 passengers, heading towards Iola...
...would a programmer say that the ERA is still zero?
More on (moron?) the 9 single-A pitcher strategy
That would depend on which engineer was on steroids.
Plymouth
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